Issue 16, 1970

Organoboron compounds. Part X. The reaction of lithium with trialkyl borates

Abstract

Lithium reacts with boiling tributyl borate to form dilithium hexabutoxydiborate Li2[(BuO)3B·B(OBu)3], which loses tributyl borate on treatment with Lewis acids, giving the salts Li2[(BuO)3B·X] where X = BF3, B(OMe)3, or SiCl4. Dilithium hexabutoxydiborate is also prepared from tetrabutoxydiboron and lithium butoxide. Tripropyl borate reacts with lithium to form the analogous compound Li2[(PrO)3B·B(OPr)3].

Article information

Article type
Paper

J. Chem. Soc. C, 1970, 2228-2229

Organoboron compounds. Part X. The reaction of lithium with trialkyl borates

R. A. Bowie, O. C. Musgrave and H. R. Goldschmid, J. Chem. Soc. C, 1970, 2228 DOI: 10.1039/J39700002228

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