Reactions of low-valent metal complexes with fluorocarbons. Part XIII. (π-Cyclopentadienyl)bis(π-ethylene)rhodium

Abstract

Treatment of [Rh(π-C₅H₅)(C₂H₄)₂] with perfluoromethyl iodide in benzene at room temperature affords [{Rh(π-C₅H₅)(CF₃)I}₂]. In contrast, perfluoropropyl iodide gives a mononuclear rhodium complex [Rh(π-C₅H₅)(C₂H₄)-(C₃F₇)I], which at 50° yields [{Rh(π-C₅H₅)(C₃F₇)I}₂]. Both binuclear complexes react with pyridine to give [Rh(π-C₅H₅)(R_F)(py)I](R_F= CF₃ or C₃F₇). Some related reactions of bis(π-ethylene)rhodium acetylacetonate are described. Reaction between [Rh(π-C₅H₅)(C₂H₄)₂] and pentafluorobenzenesulphonyl chloride affords [{Rh(π-C₅H₅)(C₆F₅)Cl}₂], from which the compounds [Rh(π-C₅H₅)(C₆F₅)(L)Cl](L = C₅H₅N, PPh₃, and H₂N·CH₂·CH₂·NH₂) can be obtained.