The derivatives of Ph2P(O)NHOH obtained using (+) and (–)-camphor-10-sulfonyl chloride rearrange with RNH2(R = But or Me) to give PhP(O)NHR having a small excess of the (+) or (–) enantiomer; this asymmetric induction is consistent with the initial product of rearrangement being a phosphonamidic–sulfonic mixed anhydride.
M. J. P. Harger and R. Sreedharan-Menon, J. Chem. Soc., Chem. Commun., 1994, 1619 DOI: 10.1039/C39940001619
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