Issue 15, 1993

Formation of azacrown complexes of Tin(IV): crystal and molecular structure of [H2L]2[SnCl5(H2O)]2·H2O·MeCN (HL = 1,4,7,10,13-pentaoxa-16-azacyclooctadecane)

Abstract

Reaction of SnCl4 and aza-18-crown-6 (1,4,7,10,13-pentaoxa-16-azacyclooctadecane, HL) provides the white solid SnCl3L 1 with elimination of HCl. Analytical and spectroscopic characterisation of 1 points to a structure in which a SnCl3 unit is bonded to the deprotonated nitrogen atom and the two adjacent oxygen atoms of the azacrown. Partial hydrolysis of 1 during an attempted recrystallisation in acetonitrile, gave colourless crystals of the ionic compound [H2L]2[SnCl5(H2O)]2·H2O·MeCN 2 the structure of which was determined by X-ray diffraction: monoclinic, space group C2/m, a= 40.15(2), b= 12.231(6), c= 10.019(7)Å, β= 104.05(5)°, Z= 4. Two independent azacrown molecules are both protonated. Molecule 1 has the solvate water molecule located centrally over the ring cavity, held by three strong O–Hwater⋯ Oring 2.793 and Owater⋯ H–Nring 2.690 Å hydrogen bonds; molecule 2 behaves as a second-sphere ligand to two separate six-co-ordinate [SnCl5(H2O)] anions positioned on opposite sides of the ring. The co-ordinated H2O molecules are located over the centre of the azacrown ligand and are involved in hydrogen bonding to the nitrogen and oxygen atoms of the ring.

Article information

Article type
Paper

J. Chem. Soc., Dalton Trans., 1993, 2359-2363

Formation of azacrown complexes of Tin(IV): crystal and molecular structure of [H2L]2[SnCl5(H2O)]2·H2O·MeCN (HL = 1,4,7,10,13-pentaoxa-16-azacyclooctadecane)

G. R. Willey, M. D. Rudd and N. W. Alcock, J. Chem. Soc., Dalton Trans., 1993, 2359 DOI: 10.1039/DT9930002359

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