Issue 15, 1990

An octanuclear Cd–Sn–(µ4-O)2 complex with bridging acetate and neopentoxide groups: [Cd4Sn44-O)2(O2CMe)10(OCH2But)10]

Abstract

Cadmium acetate and tin(IV) tetraneopentoxide react in tetrahydrofuran to form [Cd4Sn44-O)2(O2CMe)10(OCH2But)10] containing an 8-membered, Cd4O4 planar ring with cadmium ions bridged by acetates and further linked in pairs by µ4-oxo, acetate, and neopentoxide bridges to two tin(IV) atoms which in turn are bridged by neopentoxide and acetate groups.

Article information

Article type
Paper

J. Chem. Soc., Chem. Commun., 1990, 1063-1064

An octanuclear Cd–Sn–(µ4-O)2 complex with bridging acetate and neopentoxide groups: [Cd4Sn44-O)2(O2CMe)10(OCH2But)10]

C. Chandler, G. D. Fallon and B. O. West, J. Chem. Soc., Chem. Commun., 1990, 1063 DOI: 10.1039/C39900001063

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