The complex ppn[Au(acac)2]1 can be obtained by reacting ppn[AuCl2] with [TI(acac)] in 1:2 molar ratio, and complex 1 reacts with compounds of the type RH in which H has some acidic character to give the corresponding [AuR2]– species; RH = CH2(CN)22, CH2(CO2Me)23, CH2(CN)CO2Me 4, Me3SiCCH 5, 2-SH-C5H4N 6, AuR RH = CH2(PPh2)2, 7, or [AuR2]+ RH =[(4-MeC6H4)3PCH2C5H4N-2]ClO48.
J. Vicente, M. Chicote, I. Saura-Llamas and M. Lagunas, J. Chem. Soc., Chem. Commun., 1992, 915 DOI: 10.1039/C39920000915
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