Issue 2, 1981

Reactions of co-ordinated ligands. Part 23. Metalla-ring-forming reactions between hexafluoroacetone and η4-1,3-diene(η5-indenyl)rhodium complexes; the crystal and molecular structures of [Rh{OC(CF3)2CH2C(Me)[horiz bar, triple dot above]CH[horiz bar, triple dot above]CH2}(η5-C9H7)] and [Rh{OC(CF3)2C3H3C6H4}(η4-trans-C4H4Me2-1,4)]

Abstract

Reaction (room temperature) of hexafluoroacetone with isoprene- or 2,3-dimethylbuta-1,3-diene-(η5-indenyl)-rhodium affords respectively the η3-allylic rhodium(III) complexes [[graphic omitted](R2)[horiz bar, triple dot above]CH2}(η5-C9H7)](1a; R1= Me, R2= H), (1b; R1= H, R2= Me)(ratio 5 : 1), and (2; R1= R2= Me). A single-crystal X-ray diffraction study of (1a) showed that the crystals are monoclinic, space group P21/a, with Z= 4 in a unit cell of dimensions a= 14.020(7), b= 8.690(4), c= 14.669(5)Å, and β= 101.61(3)°. The structure has been solved by heavy-atom methods from automated diffractometer data, and refined to R 0.045 (R′ 0.056) for 2 704 reflections. The rhodium adopts an essentially octahedral geometry arising from η5 bonding of an indenyl ligand, a η3-allylic group formed from linking of the isoprene to the hexafluoroacetone, and a rhodium–oxygen σ bond. trans,trans-Hexa-2,4-diene(η5-indenyl)rhodium reacts with hexafluoroacetone via a different reaction path to form the rhodium(I) complex (3). A single-crystal X-ray diffraction study of (3), a tris olefin complex, showed that the crystals are monoclinic, space group P21/c with Z= 4 in a unit cell of dimensions a= 8.094(2), b= 16.962(8), c= 12.782(4)Å, and β= 99.81 (2)°. The structure has been refined to R 0.021 (R′ 0.025) for 2 878 reflections. The rhodium adopts an essentially square-planar configuration the co-ordination sites being occupied by a η4-bonded trans,trans-hexa-2,4-diene, a η2-bonded indenyl ligand, and an oxygen atom of the hexafluoroacetone molecule σ bonded to rhodium. The hexafluoroacetone is bonded to the C5 ring of the indenyl ligand. The mechanism of formation of these complexes is discussed. In contrast, hexafluoroacetone reacts with bis(ethylene)(η5-indenyl)rhodium to form ethyl(hexafluoroacetylacetonato)(η5-indenyl)rhodium.

Article information

Article type
Paper

J. Chem. Soc., Dalton Trans., 1981, 400-406

Reactions of co-ordinated ligands. Part 23. Metalla-ring-forming reactions between hexafluoroacetone and η4-1,3-diene(η5-indenyl)rhodium complexes; the crystal and molecular structures of [Rh{OC(CF3)2CH2C(Me)[horiz bar, triple dot above]CH[horiz bar, triple dot above]CH2}(η5-C9H7)] and [Rh{OC(CF3)2C3H3C6H4}(η4-trans-C4H4Me2-1,4)]

P. Caddy, M. Green, J. A. K. Howard, J. M. Squire and N. J. White, J. Chem. Soc., Dalton Trans., 1981, 400 DOI: 10.1039/DT9810000400

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