Metal complexes of sulphur ligands. Part 14. Reaction of palladium(II) and platinum(II) dithioacid complexes with tertiary phosphinites, and the crystal and molecular structure of dimethylphosphinodithioato(diphenylphosphinito)(diphenylphosphinous acid)palladium(II)
Abstract
Prolonged reaction of [Pd(S2PMe2)2] with excess PPh2(OR)(R = Me or Et) in either methylene chloride or benzene gives the four-co-ordinate complex [Pd(S2PMe2)(PPh2O){PPh2(OH)}](1a) shown by spectroscopic evidence and X-ray structural analysis to contain the symmetrically hydrogen-bonded Ph2POHOPPh2 ligand. Crystals of (1a) are monoclinic, space group P21/m, with a= 6.86(1), b= 22.12(2), c= 9.69(1)Å, β= 111.5(2)°. The acidic hydrogen atom links two equivalent diphenylphosphinite groups with O ⋯ O 2.41 Å. Similar complexes [M(S–S)(PPh2O){PPh2(OH)}](M = Pd, S–S–=[S2PPh2]– or [S2CNEt2]–; M = Pt, S–S–=[S2PMe2]– or [S2CNEt2]–) have been prepared by reaction of [M(S–S)2] with PPh2(OR) or, for M = Pd, by reaction of [{PdCl(PPh2O)[PPh2(OH)]}2] with the appropriate dithioacid anion (1 : 2 molar ratio). A careful study of the [Pt(S2CNEt2)2]–PPh2(OMe) reaction has resulted in the isolation of the intermediates [Pt(S2CNEt2){PPh2(OMe)}2]X (2; X =[BPh4]– or Cl–) and [Pt(S2CNEt2)(PPh2O){PPh2(OMe)}](3) and a mechanism of formation of [Pt(S2CNEt2)(PPh2O)(PPh2(OH)}](1b) involving both nucleophilic attack on a P–OMe bond and subsequent hydrolysis of a P–OMe bond is proposed. In contrast, reaction of [M(S2COPri)2] with PPh2(OEt) gives [M(S2CO){PPh2(OEt)}2](M = Pd or Pt), although [Pd(S2COPri)(PPh2O){PPh2(OH)}](PPh2O)[PPh2(OH)]}2] and K[S2COPri](1 : 2 molar ratio).