Issue 14, 1976
From the journal:

Journal of the Chemical Society, Dalton Transactions

Reactions of trifluoromethyl iodide with methylgold(I) complexes. Preparation of trifluoromethyl-gold(I) and -gold(III) complexes

Antony Johnson  and  Richard J. Puddephatt  

Abstract

Trifluoromethyl iodide reacts with [AuMeL] to give [AuMe2(CF3)L] and [AuIL](L = PMe3 or PMe2Ph), or [Au(CF3)L] and Mel (L = PPh3), or a mixture of these products (L = PMePh2). In some cases reaction of [AuMe(PMe3)] with CF3I gives [AuMe(CF3)I(PMe3)]. Evidence is presented that the reactions proceed, at least in part, by a free-radical chain mechanism.

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Article information

DOI
https://doi.org/10.1039/DT9760001360
Article type
Paper

J. Chem. Soc., Dalton Trans., 1976, 1360-1363

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Reactions of trifluoromethyl iodide with methylgold(I) complexes. Preparation of trifluoromethyl-gold(I) and -gold(III) complexes

A. Johnson and R. J. Puddephatt, J. Chem. Soc., Dalton Trans., 1976, 1360 DOI: 10.1039/DT9760001360

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