Issue 6, 1975

Formation of platinum–silicon, –germanium, and –tin complexes by cleavage of platinum–carbon bonds and by oxidative addition of trimethylstannane to platinum complexes

Abstract

Trimethylstannane displaces alkane from [PtR2{(Ph2P)2CH2}](R = Me or Et) at room temperature, or at 50 °C when R = Ph. The d6 product, [PtH(SnMe3)3{(Ph2P)2CH2}](I), reversibly dissociates in solution to [Pt(SnMe3)2{(Ph2P)2CH2}]. Trimethyl-silane and -germane displace only 1 mol equiv. of alkane forming [Pt(MMe3)(Me){(Ph2P)2CH2}](M = Si, Ge). The lead complex [Pt(PbPh3)2{(Ph2P)2CH2}] gives (I) and Pb2Ph6 with SnHMe3. [PtCl2{(Ph2P)2CH2}] on reaction with SnHMe3 yields the d6 complex [PtClH(SnMe3)2{(Ph2P)2CH2}](II) which dissociates to [PtCl(SnMe3){(Ph2P)2CH2}](III) in solution. Similarly, oxidative addition of SnHMe3to [Pt{(Ph2P)2CH2}2] produces [Pt(SnMe3)2{(Ph2P)2CH2}].

Article information

Article type
Paper

J. Chem. Soc., Dalton Trans., 1975, 497-498

Formation of platinum–silicon, –germanium, and –tin complexes by cleavage of platinum–carbon bonds and by oxidative addition of trimethylstannane to platinum complexes

F. Glockling and R. J. I. Pollock, J. Chem. Soc., Dalton Trans., 1975, 497 DOI: 10.1039/DT9750000497

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