Half-sandwich η-cycloheptatri-ene and -enyl derivatives of titanium and zirconium
Abstract
Treatment of [Zr(η6-C7H8)2]1 in tetrahydrofuran with iodine gives [Zr(η-C7H7)(thf)2I]2 which reacts with PMe3 forming [Zr(η-C7H7)(PMe3)2I]3. The latter reacts with iodotrimethylsilane to give the exo-trimethylsilylcycloheptatriene compound [Zr{exo-η6-C7H7(SiMe3)}(PMe3)2I2]4. Thermolysis of 4 gives [Zr(η6-C7H8)(PMe3)2I2]5. The compounds [M(η-C7H7)L2Cl][M = Ti, L2=(PMe3)26, Me2NCH2CH2NMe27 or Me2PCH2CH2PMe28; M = Zr, L2= Me2NCH2CH2NMe29] have been prepared in one-pot reactions.
- This article is part of the themed collection: Malcolm Green FRS: In celebration of his 80th Birthday