Bis(diphenylphosphino)methane complexes of ruthenium(0) and ruthenium(II)

Abstract

[Ru(cod)(cot)](cod = cyclo-octa-1,5-diene, cot = cyclo-octa-1,3,5-triene) reacts with two equivalents of bis(diphenylphosphino)methane (dppm) to yield [Ru (cod)(dppm)₂], a compound containing both a monodentate and a bidentate dppm. This reacts in turn with [Ru(cod)(cot)] to give [Ru₂(cod)₂(cot)(dppm)₂] in the solid state, with CO to give [Ru(CO)(cod)(dppm)] and [Ru(CO)₂(cod)(dppm)], and with H₂ to give a 1 : 4 mixture of trans- and cis-[RuH₂(dppm)₂]. The reaction of the dihydride with CHCl₃ and HBF₄ produces trans-[RuHCl(dppm)₂] and trans-[RuH(dppm)₂(H₂)O]BF₄, respectively. [RuH₂(PPh₃)₄] reacts with dppm to give the mononuclear complex, [RuH₂(dppm)(PPh₃)₂]. The structures of the different complexes were determined mainly using ¹H and ³¹P n.m.r. spectroscopy.