Transition metal–carbon bonds. Part XI. A crotyl–butadiene complex of iridium(III)

Abstract

Butadiene reacts with chloroiridous acid in ethanol to give a π-1-methylallyl–butadiene complex of iridium [Ir₂Cl₄(C₄H₇)₂(C₄H₆)]. Butadiene is readily displaced from this complex by neutral ligands, L, to give [IrCl₂(C₄H₇)L₂](L = 4-methylpyridine, pyridine, PPh₃, or PMe₂Ph). The complex [Ir₂Cl₄(C₄H₇)₂(C₄H₆)] is thought to have both bridging chlorine and butadiene ligands. N.m.r. data are given.