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Issue 0, 1967
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Transition metal–carbon bonds. Part XI. A crotyl–butadiene complex of iridium(III)

Abstract

Butadiene reacts with chloroiridous acid in ethanol to give a π-1-methylallyl–butadiene complex of iridium [Ir2Cl4(C4H7)2(C4H6)]. Butadiene is readily displaced from this complex by neutral ligands, L, to give [IrCl2(C4H7)L2](L = 4-methylpyridine, pyridine, PPh3, or PMe2Ph). The complex [Ir2Cl4(C4H7)2(C4H6)] is thought to have both bridging chlorine and butadiene ligands. N.m.r. data are given.

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Article type: Paper
DOI: 10.1039/J19670001972
Citation: J. Chem. Soc. A, 1967,0, 1972-1974
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    Transition metal–carbon bonds. Part XI. A crotyl–butadiene complex of iridium(III)

    B. L. Shaw and E. Singleton, J. Chem. Soc. A, 1967, 0, 1972
    DOI: 10.1039/J19670001972

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